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Show jtfWSK How to Play iBy BRIDGE I Wynne Ferguson I J&saSx Author of 'PRACTICAL AUCTION BRlDOa Copyright, 1929, by Hoyle. Jr. ARTICLE No. IS ,?nAaf thf wa7l?? "tudy the ?ame of Auction Bridge Is by comparing n J V"ll way uf bl,ddm and P'ay'ni ha"d Duplicate Auction, la fT i M.me -hands a.re played. at different tables and the final bid and the method of play is usually very different at the different tables. Here art two hands that were played in a recent tournament, held in New York City, that illustrate these points very well: Problem No. 12 Hearts K, J, 7, 5,3 ciubs 9,8, i.i.i Diamonds none ,. . Spades Q, 9, 3 -hfh?tn'9,f' Hearts-10. 8, 2 Jubs 10,6 4 j y i Club. Q,i felfc8'3 A z B; sDidT.-TAJ'10'9'M'a Hearts Q . Clubs A, K.J Diamonds K, 7, S Spades K, 10, 8, 7, 6, 2 No score, first game. (1) Suppose Z )ids one spade and A bids one no :rump. What should V bid? (2) Suppose Sup-pose Y bids two hearts and B bids three iiamonds, what should Z bid? (3) Suppose Sup-pose Z passes, A bids three no trump jnd all pass, what should Y open? (4) Suppose Y opens the three of spades, what should Z play? Think over these various questions and decide whether or not the suggested bidding is correct. An analysis of the hand and of what happened at various tables in the tournament game will be given in the next article. Problem No. 13 Hearts A, Q, 5, 3, 2 Clubs Q, 3 i Y t Diamonds 7,5 jA B: Spades K, Q, 9,5. i . t Z t No score, first game. Z dealt and bid one club, A bid one heart, Y passed and B bid two diamonds. (1) If Z now bid two spades, what should A do? (2) If A end Y passed, B bid three diamonds and.Z passed, what should A now do? Ar - naJysis of the bidding of this hand will be given in the next article. Answer to ProbLm No. 10 '. . Hearts A, K, 0,9 i Clubs A, 8, j Diamonds K, 7, 3 . ... Spades Q, 9, 8 Hearts - 7 4, 2 Hearts J, 10, 6, 3 Clubs 6, 5, 2- : v . rinh.i7 t hi Hearts 8, 5 Clubs Q, 10, 9' Diamonds 8, 6, 2 Spades A, K. J, 10,4 No score, rubber game. Z dealt and id one spade. A and Y passed and B loubled. (Informatory). Z, the dealer, ith a very strong hand, bid two ipades over the double and all passed. A opened the jack of diamonds and B were thus able to win the first .hree tricks. At the fourth trick, B. tho was in the lead, led the five of pdcs. The problem is for Z to so play he hand that he will win the balance f the tricks against any defense. ; Soiutiim: The point of this hand is t Z to win the first spade trick in Y's land and then play the ace of clubs. The play of the ace of clubs is the key play of the hand for it enables Z to lead out the remaining trumps. Y must make two discards and the play of the ace of dubs enables Y to discard his two remaining clubs. B must make four discards. He can discard one diamond dia-mond and two clubs, but what will his fourth discard be? If he'discards a third club, Z's queen of clubs will be good. If he discards a heart, Y's hearts will be good. Whatever B discards, i therefore, on the ninth trick, Y Z must win the balance of the tricks. I i- - t Answer to Problem No. 11 Hearts nova ! Clubs A, K ' ' Diamonds A, 5, 4 , . . Spades A, Q, 5 7 !A B : Eian?o7d.7-i'lSd4 spades -i K, J, 6 s Z , Spades 9 Hearts Q, T Clubs 9,8 Diamonds 3, 2 Spades 3, 2 There are no trumps and Z is in the eid. How can Y Z win all of the tricks against any defense? Solution : Z should lead the queen and iack of hearts. A and B follow suit and Y should discard the ace and king of rhibs. Z should now lead the nine of clubs. A should discard the seven of diamonds and Y the four of diamonds. Z should now lead the eight of clubs. A can do one of two things: (1) discard dis-card the jack of diamonds or (2) the tight of spades. (1) Suppose A discards tlm iark of diamonds. Y should discard the five of spades. Z should now lead ! the deuce of spades, finesse the queen in Y s hand and thus win the balance of the tricks with the ace of spades and the ace and five of diampnds. (2) gup- I. pose A "discards the eight of spades Y ' should discard the five of diamonds. Z should now lead thj deuce of spades, j finesse the queen and thus will win the 1 balance of the tricks with the ace and five of spades and the ace of diamonds. It is a pretty little problem in the forcing of discards and should be carefully care-fully ctudierl. |