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Show rfjs. How to Play Wmiv BRIDGE eries i$a)'30 by I Wynne Fergusoa 1 j I ir Author of 'PRACTICAL AUCTION BRlDM?4- t l Copyright. t29. by Hoyte. Jr. - Hlfe ARTICLE No. 9 , . The second Annual Eastern Bridge Tournament was held at New York City, and it proved to be a great success. suc-cess. There were eighteen teams entered en-tered in the Championship Team of Four Event, the largest number ever entered in such a Tournament. The Cavendish Club team, headed by the redoubtable R. J. Leibenderfer, was the winner. The other members of the winning team were E. S. VVeUlar, R. Balfe and G. Scott This is the second rear in succession that Mr. Leibenderfer has headed the winning team, as Its also won last year, playing for the Knickerbocker Whist Club. The victory vic-tory for The Cavendish Club was remarkable re-markable in view of the class of competition compe-tition and the fact that the Club is only two years old. To develop a championship champion-ship team in such a limited time is indeed an achievement. Here is one of the hands played during the tournament that shows the value of a clever defense : Heart Q, 7,5 Club 9, 8,6 Diamond K, 10, 8, 5, $ Spade J, 4 Heart A J. 10, 9, S, I V t Club. A 10, 7, J I A B i Diamond 3 Z i Spade 10,2 No score, first gam. Z dealt and bid one spade. A passed, Y passed and B bid two hearts. Z bid two spades. A snd Y passed and B bid three hearts. Z bid three spades and all passed. A opened the eight of hearts, Y played the five. B the ace and Z a low heart. What should B now play? If you will stop to think a minute, it will be evident evi-dent that in order to cave game A must hold either the ace of spades or the ace of diamonds. If Z hold both aces, there is no way for B to save game. His proper lead, therefore, i the deuce of iiainond. If A holds the ace of that suit, he can give B the ruff. If ha hasn't the ace of diamond but does have the ace of spades, he can win the first spade trick and lead back a diamond, dia-mond, thus again giving B a chance to ruff. The play is well thought out and the player who made it wae the only one to save game on that hand. A' hand was as follows) Hearts 8,4 Clubs -Q.J 4, 3.2 Diamond Q, 9, 4 Spade Aii 3 The defensive play In the foregoing hand is very clever, so note it carefully. Answer to Problem No. 3 ' Heart J Club Q - Diamond K, 7 ,nn Spade K, 8, 4,2 Bearts-lOO Hearts -none Club. J, 10. 8 t Y t Clubs 9,4 DUmonda Q, 9 lA Bt Diamond. 3, Spades 9 t Z I Spade A, J, 0, 1 Hearts 8, 6 Club K, 7, 6 .is Diamond none st) Spade Q, 10, 7 - . There are no trump and Z is in the cad. How can Y Z win seven of the eight tricks against any defense? Solution: Z should lead the six of club, winning the trick in Y's hand with the queen. Y should now lead the deuce of spades. B can either play the tv of spade or the ace of spades. (a) Suppose he plays the five of spades. Z should play the ten of spades and A follows suit. Z' best play now is the king of clubs and Y should discard the seven of diamonds, the others following fol-lowing suit. The object of this play is to exhaust B's clubs before he is forced in the lead. Z should now lead the six of hearts, winning the trick in Y's hand with the jack. B is thus forced to discard. dis-card. He can discard either a low spade or the trey of diamonds. If he discards a low spade, Y should lead the four of spade and B can either play the ace or the jack. If he plays the ace, Y's spades and the king of diamonds are good. If he plays the jack, Z should win the trick with the queen of spades and return the seven of spades, thu forcing B in the lead. B must now lead a diamond dia-mond and Y win the balance of the trick. B's best discard, therefore, on the jack of hearts is the trey of diamond. dia-mond. Y (hould then lead the king of diamond. The object of this play is to exhaust the diamonds in B's hand. Y should then lead the four of spades. B can then play either the ace, jack or six of spades. If he play the ace. Z should play the queen of spades ana B Is then forced to lead up to Y's king and eight of spades so that Y must win the balance of the tricks. If B plays the jack of spades, Z should play the queen of spades and return the seven of spade. B can win this trick and then must lose the six of spades. If B play the six of spades, Z should play the seven of spades and return the qneen of spade. B win this trick and then must lose the jack of spades. (b) Suppose at trick No. 2, B should play the ace of spades. B can now lead either the nine of club or the trey of diamonds. (1) Suppose he lead the mne of clubs. Z should win the trick with the king of clubs and Y should discard the four of spades. Z should . now lead the ten of spades and win the trick in Y's hand with the kins of spades. A is thu forced to discard. If he discards a heart, he set up a heart trick in Z's hand and Y Z must thus win the balance of the trick. If A discards dis-cards a club, he likewise set up a club in Z's hand and Y Z must win the balance of the tricks. If A discards a ' '"' , diamond, both of Y's diamond are good so once again YZ must win all of the tricks. (2) Suppose at trick three T B should lead the trey of diamonds. Y should win the trick with the king of 'r diamonds and lead the four of spades. Z should win the next two spade tricks j ' ' " with the queen ten of spade and than . - - lead the kimr of club on which Y should discard the seven of diamond. Z should then lead a heart which Y should win and lead his king of spades, thus again winning the balance of the trick. " If at trick three, B (hould lead a t - V spade, practically the same result would V . follow and Y Z would again win the , balance of the trick. There seems to vw be no way, therefore, for A B to win sv; - f more than one trick no matter what ' defense they adopt It is a tricky little , - problem and bring out many fine ' ' 1 t point of defsnat Study it carefully, ' "' , - ' -) : L - " |